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issues with bash commands as variables (monero.town)
submitted 10 months ago* (last edited 10 months ago) by shortwavesurfer@monero.town to c/programming@beehaw.org
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Any ideas? I am attempting to write a script that uses sed.

If done this way it fails

  • rmdec="sed 's/..................$//'"
  • i1xmr=$(echo "$i1p/$apiresponse*1000" |bc -l |$rmdec)

But if i do it this way it works

  • i1xmr=$(echo "$i1p/$apiresponse*1000" |bc -l | sed 's/..................$//')
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[-] shortwavesurfer@monero.town 1 points 10 months ago

Hmm. I had a look at the example given. I see the idea, but would cat be the thing to use or would it be echo <<-EOF > "$file"?

[-] bizdelnick@lemmy.ml 1 points 10 months ago

You need cat because it reads stdin and prints it to stdout. echo does not read stdin, it prints its arguments.

[-] shortwavesurfer@monero.town 1 points 10 months ago

I have never used cat like that before. If you just ent cat abcd > file it says abcd doesnt exist but does create "file". I know you can cat contents of a file into another file but why the <<-EOF > file works is a bit beyond me.

[-] bizdelnick@lemmy.ml 1 points 10 months ago

cat does not create file, your shell does when you redirect the standard output with > file.

this post was submitted on 24 Oct 2023
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